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Lf f(x) = 4x³ + Ax² + 7x − 1 and f(2) = 7, what is the value of A?​

User ArkadyB
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1 Answer

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Answer:

4(2)³+A×2²+7(2)-1=7

4×8+4A+14-1=7.

32+14-1-7=-4A..

38=-4A.

A=38/-4.

A=-9½

User Amadou
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