Question

Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down the runway. A smaller plane with the same acceleration has a takeoff speed of 40 m/s . Starting from rest, after what distance will this smaller plane reach its takeoff speed?

Answer 1

300 m

Step-by-step explanation:

Find acceleration of first plane

v = a t

80 = a (30) shows a = 2.67 m/s^2

For the smaller plane

v = at

40 = 2.67 t shows t = 14.98 seconds

d = 1/2 a t^2

= 1/2 2.67 (14.98^2) = 299.6 = ~ 300 meters

Answer 2

Answer:600 m is required for smaller plane to reach its takeoff speed. ... So 300 m is required for smaller plane to reach its takeoff speed.

Step-by-step explanation: