85.7k views
2 votes
X+y+3z=-4
-x+y-2z=5
2x-z=-3

1 Answer

4 votes

Answer:

x = -2, y = 1, z = -1

Explanation:


- \begin{cases}x + y + 3z = -4 \\ -x + y - 2z = 5 \\ 2x - z = -3\end{cases} \text{ / Subtract all of the equations} \\ \\\to x + y + 3z - (-x + y - 2z) - (2x - z) = -4 - 5 - (-3) \\ \\\to x + y + 3z + x - y + 2z - 2x + z = -4 - 5 + 3 \\ \\\to 6z = -6 \\ \\\to z = -1 \\ \\\text{Substitute z = -1 into the 3rd equation to find x:} \\ \2x + 1 = -3 \\\to 2x = -4 \\\to x = -2 \\ \\\text{Substitute z = -1, x = -2 into the first equation to find y:} \\-2 + y - 3 = -4 \\\to y - 5 = -4 \\\to y = 1

User Valentine Shi
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories