Question

PLS HELP WILL GIVE 30 POINTS

Answer 1

Answer:
`y=-(1)/(3) x^2 +(2)/(3)x+(26)/(3)`

Explanation:

The equation in vertex form is
`y=a(x-1)^2 +9`.

Substituting in the coordinates (4,6) to solve for a,

`6=a(4-1)^2 +9\\\\6=9a+9\\\\9a=-3\\\\a=-(1)/(3)\\\\`

This means the equation in vertex form is
`y=-(1)/(3)(x-1)^2 +9`. Expanding this out into standard form,

`y=-(1)/(3)(x^2 -2x+1)+9\\\\=-(1)/(3)x^2 +(2)/(3)x-(1)/(3)+9\\\\=-(1)/(3)x^2 +(2)/(3)x+(26)/(3)`