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Igcse math (quadratic functions)

given the equation: x^2 + 5x - 14
use the discriminant to decide if there are two real and different roots, two equal roots or no real roots

User Gregdim
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1 Answer

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5 votes

Answer:

2 real different roots

Explanation:

Discriminant determines the number of real solutions of a quadratic equation. The formula of discriminant goes by:


\displaystyle{D = b^2-4ac}

The formula is derived from a quadratic formula which is:


\displaystyle{x=(-b\pm √(b^2-4ac))/(2a)}

The expression inside the square root is discriminant. The discriminant says that:

  • There are 2 real different roots if the discriminant (D) is greater than 0. (D > 0)
  • There is 2 real double roots (same roots) if the discriminant (D) is equal to 0. (D = 0)
  • There are no real roots (imaginary or complex roots) if the discriminant (D) is less than 0. (D < 0)

From the equation
\displaystyle{x^2+5x-14}, determine the coefficients of equation:

  • a = 1
  • b = 5
  • c = -14

Therefore, substitute the coefficients’ values in the discriminant:


\displaystyle{D=5^2-4(1)(-14)}\\\\\displaystyle{D=25-4(-14)}\\\\\displaystyle{D=25+56}\\\\\displaystyle{D=81}

Since the discriminant is greater than 0, we can conclude that this equation will have 2 real different roots.

User Sujay DSa
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