Our water faucet leaked 3 2/6 liters of water every 3/5 of a hour.
We are to find the rate in liter per hour at which the water faucet leaked.
First, use the number of liters the water faucet leaked in 3/5 of a hour.
This is 3 2/6 = 20/6
Therefore, the number of liters of water faucet leaked in 1 hour is
(20/6) / (3/5)
Before we solve this, we should simplify,
20/6 can be simplified to 10/3
3/5 cannot be simplified
Then, we should modify our problem to use reciprocation instead of a complex fraction,
(10 • 5) / (3 • 3)
This equals 50/9
Now, solve 50/9 for 5.555555555556
This rounds to 5.6
Thus, the required rate at which the water faucet leaked is 5.6 liters per hour.