Question

Help ...........................................................

Answer 1

`{ \qquad\qquad\huge\underline{{\sf Answer}}}`

Let's solve ~

`\qquad \sf  \dashrightarrow \: y = 2x - 3`

plug the value of x = -5 :

`\qquad \sf  \dashrightarrow \: y = 2( - 5) - 3`

`\qquad \sf  \dashrightarrow \: y = - 10 - 3`

`\qquad \sf  \dashrightarrow \: y = - 13`