Question

215,36,6 find the seventh term


Pls help

Answer 1

Answer: 216, 36, 6, 1, 1/6, ...

Explanation:

216, 36, 6, ...

`b_1=216\\b_2=36\\b_3=6\\\displaystyle\\q=(b_2)/(b_1) \\\\q=(36)/(216) \\\\q=(1)/(6) \\\\q=(b_3)/(b_2) \\\\q=(6)/(36) \\\\q=(1)/(6) \\\\Hence,\\\\b_n=b_1q^(n-1)\\\\b_5=216*((1)/(6))^(5-1)\\\\b_5=216*((1)/(6) )^4\\\\b_5=216*(1)/(6^4)\\\\b_5=6^3 *(1)/(6^4) \\\\b_5=(6^3)/(6^4) \\\\b_5=6^(3-4)\\\\b_5=6^(-1)\\\\b_5=(1)/(6)`