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a bullet has a mass of 0.013 kg is shot out of a rifle barrel with the speed of 750 m/s. What is the bullet’s kinetic energy?

User Carl Bosch
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1 Answer

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Step-by-step explanation:

K.E = 1/2 m v²

kinetic energy= 1/2 × mass × velocity²

kinetic energy = 0.5 × 0.013 × 750²

= 3656.25 J

User LordScone
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