Question

a bullet has a mass of 0.013 kg is shot out of a rifle barrel with the speed of 750 m/s. What is the bullet’s kinetic energy?

Answer 1

Step-by-step explanation:

K.E = 1/2 m v²

kinetic energy= 1/2 × mass × velocity²

kinetic energy = 0.5 × 0.013 × 750²

= 3656.25 J