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5 votes
Two towns are 52 km apart. Buses travelling

between the two towns leave at the same
time but travel in opposite directions. The
bus from town A is travelling 80 km/h and
the bus from town B is travelling 70 km/h.
How long after they leave will they pass each
other? (Reminder: there are 60 minutes in an
hour!)

1 Answer

5 votes

Explanation:

x = number of km bus from A drives until they meet.

y = number of km bus from B drives until they meet.

x/80 is the time for the bus from A to reach the meeting point.

x/70 is the time for the bus from B to reach the meeting point.

both times must be equal, as they start at the same time.

so,

x/80 = y/70

but then we also know that together they have traveled the full 52 km to meet.

so,

x + y = 52

x = 52 - y

with that we go into the first equation :

(52 - y)/80 = y/70

(52 - y)/8 = y/7

7×(52 - y)/8 = y

7×(52 - y) = 8y

364 - 7y = 8y

364 = 15y

y = 364/15 km = 24.26666666... km

x = 52 - y = (780-364)/15 = 416/15 = 27.73333333... km

they will meet after (using bus from B)

364/15 / 70/1 = 364/1050 hours

= 182/525 hours =

= 60×182/525 = 10920/525 minutes =

= 728/35 = 104/5 = 20.8 minutes =

= 20 minutes 60×8/10 seconds =

= 20 minutes 48 seconds

control (using bus from A) :

416/15 / 80/1 = 416/1200 hours =

= 26/75 hours =

= 60×26/75 = 1560/75 minutes =

= 104/5 = 20.8 minutes

correct.

User Erikbozic
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