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39 votes
39 votes
A spring with k = 136 N/m is compressed by 12.5 cm. How much elastic potential energy does the

spring have?

User Vishwanath Dalvi
by
2.5k points

1 Answer

9 votes
9 votes

As we know,


  • \boxed{ \boxed{potential \: \: energy = (1)/(2) k {x}^(2) }}

where,

  • k = 136 N/m

  • x = 12.5 cm = 0.125 m

now, let's solve to find potential energy :


  • p = (1)/(2) * 136 * 0.125 * 0.125


  • p = \frac{68 * 125 * 125} {1000 * 1000}


  • 1.0625 \: \: \: joules
User Padrus
by
2.4k points