Question

A spring with k = 136 N/m is compressed by 12.5 cm. How much elastic potential energy does the

spring have?

Answer 1

As we know,

• 
  `\boxed{ \boxed{potential \: \: energy = (1)/(2) k {x}^(2) }}`

where,

• k = 136 N/m

• x = 12.5 cm = 0.125 m

now, let's solve to find potential energy :

• 
  `p = (1)/(2) * 136 * 0.125 * 0.125`

• 
  `p = \frac{68 * 125 * 125} {1000 * 1000}`

• 
  `1.0625 \: \: \: joules`