Question

Three horizontal forces are pulling on a

ring, at rest. Fy is 6.25 N at a 180° angle,
and F2 is 8.90 N at a 243° direction. What
is the x-component of F3?

Answer 1

-(F1+F2)y

Step-by-step explanation:

add up F1 and F2 using x-y components

Since the three forces balance,

F3y = -(F1+F2)y

Answer 2

Answer: 10.29

Step-by-step explanation:

F1: 6.25cos(180°) = -6.25

F2: 8.90cos(243°) = -4.04

F3: -6.25 + (-4.04) = 10.29