Question

the abscissa of a point is -6 and its distance from the point (1,3) is √74. find the ordinate of the point​

Answer 1

The ordinate of the point with an abscissa of -6 and at a distance of √74 from (1,3) is either 8 or -2, after applying the distance formula and solving for y.

Step-by-step explanation:

To find the ordinate of the point whose abscissa is -6 and which is at a distance of √74 from the point (1,3), we use the distance formula between two points. The distance formula is √((x2 - x1)2 + (y2 - y1)2). In this case, we have one point (x2, y2) as (-6, y) and the other point (x1, y1) as (1,3).

Squaring the distance given, we get 74 = ((-6 - 1)2 + (y - 3)2). This simplifies to 74 = (49 + (y - 3)2). After subtracting 49 from both sides of the equation, we get (y - 3)2 = 25. Taking the square root of both sides gives us y - 3 = ±5. Therefore, the ordinate y can be either 3 + 5 or 3 - 5, which is 8 or -2.

Answer 2

`\huge\fbox{Answer ☘}`

we know that ,

• absicca of a point = x - coordinate of that point

• ordinate of a point = y - coordinate of that point

‎

therefore , let the point be A( -6 , y )

also ,

we're given an another point , i.e. ,

B( 1 , 3 )

therefore , the ordinate of point A is either ( -8 ) or ( 2 )

hope helpful~