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Find the area of a triangle bounded by the y axis, the line f(x)=10-3/4x, and the line perpendicular of f(x) passes through the origin.

User Tecla
by
5.3k points

1 Answer

8 votes

Answer:


(200)/(3) square units

Explanation:

Knowing the function and that the triangle is formed by both the x and y-axis, you already have the triangle's height, which is 10 (the y-intercept of the functon) To find the base length, all you have to do is find the x-intercept. To do that, simply:

Set function equal to 0 and solve for x:

f(x) = 10 -
(3)/(4) x

0 = 10 -
(3)/(4) x


(3)/(4) x = 10

x =
(40)/(3)

This means that the base length of the triangle is also
(40)/(3). Now that you have the height and base length, you can

Plug values into the formula for the area of a triangle:

The area of a triangle is
(1)/(2) × height × base

Height = 10, base =
(40)/(3)

Area =
(1)/(2) × 10 ×
(40)/(3)

Area = 5 ×
(40)/(3)

Area =
(200)/(3)

User Ben Pearson
by
4.6k points