143k views
1 vote
Solve for x.

2x+3≤x−5

x≤2

x≤8

x≤2

x≤8

1 Answer

4 votes

Answer:

1st and 3rd answers are correct.

Explanation:


\sf2x + 3 \leqslant x - 5

First, to take x left side, subtract x from both sides.


\sf2x + 3 - x \leqslant x - x - 5 \\ \sf \: x + 3 \leqslant - 5

To take 3 to the left side, subtract 3 from both sides.


\sf \: x + 3 - 3 \leqslant 5 - 3 \\ \sf \: x \leqslant 5 - 3 \\ \sf \: x \leqslant 2

User Ahmed Fwela
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