Question

Solve for x.

2x+3≤x−5

x≤2

x≤8

x≤2

x≤8

Answer 1

1st and 3rd answers are correct.

Explanation:

`\sf2x + 3 \leqslant x - 5`

First, to take x left side, subtract x from both sides.

`\sf2x + 3 - x \leqslant x - x - 5 \\ \sf \: x + 3 \leqslant - 5`

To take 3 to the left side, subtract 3 from both sides.

`\sf \: x + 3 - 3 \leqslant 5 - 3 \\ \sf \: x \leqslant 5 - 3 \\ \sf \: x \leqslant 2`