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Tony started to work at a company in the year 2001. His yearly salary was $26,500. At the beginning of the next year he received a $2,880 raise. Assume that he receives the same raise each year. Write a function to find Tony’s salary n years after 2001.

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3 votes

Answer:

y=2880x+26500

Explanation:

Basically, this question wants you to write an equation where you can figure out how much money Tony has at any year.

1. They already told us how much the raise was: $2880

2. He started off with $26,500, so we know we have to add that at the beginning. That is our y-intercept.

3. A function is written as y=mx+b. Y is what you are solving for. M is the constant change (x doesn't mean anything, it just tells us which number is m). B is the y-intercept, which is 26,500 in this case. Its what you are starting with. If he had no money, there would be nothing to start with. There would be no y-intercept.

4. Because he gets the same raise every year of 2880, that is constant. It does not change, but it increases constantly.

5. So, y=2880x+26500 is your answer.

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