Piecewise defined functions

asked Oct 13, 2023 8.1k views

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Part a

$(\pi)/(3) > (\pi)/(4) \implies f(\pi/3)=\sin(\pi/3)=\boxed{(√(3))/(2)}$

Part b

$(\pi)/(6) \leq (\pi)/(4) \implies f(\pi/6)=2+\cos(\pi/6)=\boxed{2+(√(3))/(2)}$

Part c

$(\pi)/(4) \leq (\pi)/(4) \implies f(\pi/4)=2+\cos(\pi/4)=\boxed{2+(1)/(√(2))}$

Calum Halpin answered Oct 19, 2023

4.6k points

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