69.7k views
1 vote
What is the line of symmetry for the parabola whose equation is y=x²-12x + 7?

Ox=12
Ox=6
Ox=-6

2 Answers

2 votes

Answer:

x = 6

Step-by-step explanation:

The axis of symmetry of a parabola is the x-value of its vertex.

For a quadratic function in the form
y=ax^2+bx+c, the x-value of the vertex is:


x=-(b)/(2a)

Given function:


y=x^2-12x+7

Therefore:


a=1, \quad b=-12, \quad c=7

So the axis of symmetry of the given quadratic function is:


\implies x=-(b)/(2a)=-(-12)/(2(1))=(12)/(2)=6

User Mxb
by
8.6k points
3 votes

Answer:

x = 6

Step-by-step explanation:

completing square:


y=x^2-12x+7


y=(x^2-12x)+7


y=(x-6)^2+7-(-6)^2


y=(x-6)^2+7-36


y=(x-6)^2-29

Comparing with quadratic equation
y=ax^2 + bx+c, in vertex form where
y = a(x-h)^2+k. In this x - h = 0, x = h defines the symmetry of equation.

So here the symmetry for parabola:

x - 6 = 0

x = 6

User Aerique
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories