Answer:
19 tables
Explanation:
Let X represent the number of tables that have 1 student and 3 seniors
Let Y represent the number of tables that have 2 student2 and 4 seniors
Therefore number students total
1X + 2Y =23 (1)
Number of seniors total
3X + 4Y = 61 (2)
Multiply equation (1) by 2 giving
2X + 4Y = 46 (3)
Subtract (3) from (2)
3X + 4Y - (2X+4y) = 61-46
3X + 4Y - 2X -4Y = 15
3X-2X = 15
X = 15
Plugging this value into equation (1) gives
1(15) + 2Y = 23
15 + 2Y = 23
Subtract 15 from both sides
2Y = 23 - 15
2Y = 8
Divide by 2 both sides
Y = 4
Thus total number of tables used = X +Y = 15+4 = 19