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What lines would you use to solve –3x – 2 = 2x + 8? Graph the line for the left side of the equation. Graph the line for the right side of the equation.

User Bvanderw
by
4.3k points

2 Answers

2 votes

Answer:

See attached graph for lines

Left side line is y = -3x-2

Right side line is y = 2x + 8

Point of intersection is at (-2,4)

Explanation:

The line graphs are attached

The solution for (x, y) is the point of intersection of the two lines

This is at point (2,4)

We can also solve this algebraically by solving first for x and then y

–3x – 2 = 2x + 8

The two line equations are

y = -3x - 2 and y = 2x+8

3x – 2 = 2x + 8

==> 3x -2x - 2 = 2x-2x + 8 (subtract 2x on both sides)

==> -5x -2 = 8

==> -5x -2 + 2 = 8 + 2 (add 2 on both sides to isolate the x term)

==> -5x = 10==> -5x/5 = 10/5 (divide by 5 both sides)

==> x = -2

Plug this value of x into the RHS giving

y = 2(-2) + 8 ==> y = -4 + 8 ==> y = 4

So (-2,4) is the point of intersection of the two lines and is consistent with the point of intersection on the graph

What lines would you use to solve –3x – 2 = 2x + 8? Graph the line for the left side-example-1
User Canova
by
4.6k points
5 votes

Answer: C & A

Explanation:

User Ries Vriend
by
5.4k points
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