Question

One number is six less than three times another number. If the sum of the numbers is 38, find the numbers

Answer 1

consider the two number as x and y

first given condition

x-6 = 3y

i.e. x= 3y + 6 eqn 1

second given condition

x+ y = 38

i.e. x= 38-y eqn 2

solving eqn 1 and 2

3y + 6 = 38-y

3y + y = 38-6

4y = 32

y = 8

substituting the value of y in eqn 2

x = 38 - y

x= 38-8

x= 30

hence the required numbers are 8 and 30