Question

A pool is 31.4 m long and 40.0 m wide. if the average depth of water is 3.30 ft, what is the mass (in kg) of water in the pool? enter your answer in scientific notation.

Answer 1

31.4 * 40.0 = 1256 m^2

1 m = 39.37 in = 3.28 ft

3.30 ft = 1.01 m

Volume of pool = 1256 * 1.01 = 1264 m^3

Since 1 m^3 water contains 10^3 kg the volume of the pool is

1.264E3 * E3 = 1.264E6 kg

(or 1.264 * 10^6 kg)