Question

A car starts from rest and covers a distance while accelerating the final velocity is very determine an expression for the cars acceleration

Answer 1

Explanation:

Time taken t=5.21s

Initial velocity u=0 and distance traveled s=110m

Using, s=ut+at2/2

where a is the acceleration.

⇒110=0(5.21)+a(5.21)2/2

We get a=8.10m/s2

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