Question

Pls help this is prettty urgent

Answer 1

Answer: See explanation

Explanation:

3. a. Make a table and plug in 5 x values ranging from -3 to -1.

(x^2-4)/(x^2+5x+6)=

(x-2)(x+2)/(x^2+2x+3x+6)=

(x-2)(x+2)/(x(x+2)+3(x+2))=

(x-2)(x+2)/((x+3)(x+2))=(x-2)/(x+3)

(-2-2)/(-2+3)=

-4/1=-4

b.x->
`-3^(-)`: (
`-3^(-)`-2)/(
`-3^(-)`+3)=

-5/(-0.000..1)=

5/(0.000...1)= ∞

x->
`-3^(+)`:(
`-3^(+)`-2)/(
`-3^(+)`+3)=

-5/(0.000...1)= -∞

c. When you simplify g(x) to (x-2)/(x+3), x=-2 is valid, but x=-3 would make the denominator equal to 0 which is illegal.