Answer:
10, 20, 30
Explanation:
You want three numbers divisible by both 2 and 5.
Common multiples
In order for a number to be divisible by 2, it must have 2 as a factor. If it is to be divisible by 5, it must have 5 as a factor. You want numbers divisible by both 2 and 5, so both 2 and 5 must be factors of the numbers. The values 2 and 5 have no factors in common, so their least common multiple is 2×5 = 10.
Any integer multiple of this value will be divisible by both 2 and 5. A multiple of 10 will end in 0. That is, any integer with a units digit of 0 is divisible by both 2 and 5. Examples are ...
10, 20, 30