Answer: 1. (p^2 - 6)(1 - q(p^2 - 6)) 2. (a - b)(z + a - b)
Explanation:
In the first question think of p^2 - 6 as the letter A. You would get A - q A^2, factorizing it to get A(1-qA). Then substituting the A with the p^2 - 6, you would get (p^2 - 6)(1 - q(p^2 - 6))
Now in the next question, you need to understand the priniciple
(a - b) ^ 2 = (b - a) ^ 2
As a^2 - 2ab + b^2 = b^2 - 2ab + a^2
So we get z(a - b) + (a - b) ^ 2 and using the same technique from the last question, you get (a - b)(z + a - b)
Hope this helps!!!