Question

What is the midpoint of AC on the grid below?

Answer 1

(- 1, 1 )

Explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

(
`(x_(1)+x_(2) )/(2)` ,
`(y_(1)+y_(2) )/(2)` )

here (x₁, y₁ ) = A (2, 4 ) and (x₂, y₂ ) = C (- 4, - 2 ) , then

midpoint = (
`(2-4)/(2)` ,
`(4-2)/(2)` ) = (
`(-2)/(2)` ,
`(2)/(2)` ) = (- 1, 1 )