Question

Sin(A+B)+sin(A-B)=2sinAcosB​

Answer 1

True

Explanation:

sin(A+B) + sin(A-B) = 2sin(A)cos(B)​

`sin(t)+sin(s) = 2sin((t+s)/(2) )cos((t-s)/(2) )`

`sin(a+b) + sin(a-b) = 2sin(((a+b)+(a-b))/(2))cos(((a+b)-(a-b))/(2) )`

`2sin(((a+b)+(a-b))/(2))cos(((a+b)-(a-b))/(2) )`

`2sin(((a+a)+(b-b))/(2))cos(((a-a)+(b+b))/(2) )`

`2sin((2a)/(2))cos((2b)/(2) )`

`2sin(a)cos(b)`

Answer 2

Answer: sin(A+B)+sin(A-B)=2sinAcosB​

Explanation:

sin(a+b) = sin(a)cos(b)+cos(a)sin(b)

sin(a-b) = sin(a)cos(b)-cos(a)sin(b)

sin(a)cos(b)+cos(a)sin(b)+sin(a)cos(b)-cos(a)sin(b) = 2sin(a)cos(b)