Question

A line 5y = px - 4 passes through the point (7,2). Find the value of p. 2 Given that the point (-1,q) lies on this line, find the value of q. Explain why the point (2,-3) does not lie on this line. (a) (b) (c)​

Answer 1

p=2, q=-1.2

Explanation:

Q1. Sub x=7, y=2 into eqn 5y = px-4:

5(2) = p(7)-4

7p-4 = 10

7p = 14

∴ p = 2

Q2. Sub x=-1, y=q, p=2 into eqn 5y = px-4:

5(q) = 2(-1) - 4

5q = -2 - 4

5q = -6

∴ q = -1.2