Question

Find the 14th term of the geometric sequence 7,28,112

Answer 1

We are to find the 14th term in the G.P sequence: 7, 28, 112.........n

1st term (a)
`= 7`

Common ratio:
`(28)/(7) = 4`

Formula for finding the nth term of a G.P:
`tn = a {r}^(n - 1)`

Where: t = term, n = the given number of term, a = the 1st term, and r = the common ratio.

Replacing for the values of the variables in the above formula.

`t14 = 7 * {4}^(14 - 1)`

`t14 = 7 * {4}^(13)`

`t14 = 7 * 67108864`

`t14 = 469762048`

Therefore: the 14th term = 469762048

I hope this helps.

Answer 2

Answer: 469762048

Explanation:

1: 7*4^0=

7*1=7

2:7*4^1=

7*4=28

3: 7*4^(3-1)=

7*4^2=

7*16=112

14: 7*4^(14-1)=

7*4^13=469762048