Question

What values of b satisfy 4(3b + 2)2= 64

Answer 1

b = 2

Explanation:

4(3b+2)2 = 64

4×2=8

8(3b+2) = 64

`(8(3b+2)=64)/(8)` Divide by 8 on both sides of equation.

3b+2 = 8 Subtract 2 from both sides of equation.

-2 -2

`(3b = 6)/(3)` Divide by 3 on both sides of equation.

b = 2