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What values of b satisfy 4(3b + 2)2= 64
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What values of b satisfy 4(3b + 2)2= 64

User Labago
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1 Answer

2 votes

Answer:

b = 2

Explanation:

4(3b+2)2 = 64

4×2=8

8(3b+2) = 64


(8(3b+2)=64)/(8) Divide by 8 on both sides of equation.

3b+2 = 8 Subtract 2 from both sides of equation.

-2 -2


(3b = 6)/(3) Divide by 3 on both sides of equation.

b = 2

User Auskennfuchs
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