33.6k views
3 votes
Find the derivative of g(y)=(y-4)*(2y+y^2)

User Isxek
by
7.7k points

1 Answer

4 votes

Answer:


g'(y)=3y^2-4y-8

Explanation:

start by foiling out the given function


g(y)=(y-4)(2y+y^2)\\=2y^2+y^3-8y-4y^2\\=y^3-2y^2-8y

next, use the power rule to find the derivative

power rule: To use the power rule, multiply the variable's exponent n, by its coefficient a, then subtract 1 from the exponent. If there's no coefficient (the coefficient is 1), then the exponent will become the new coefficient.


g'(y)=3y^2-4y-8

User Terrence Brannon
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories