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Find the derivative of g(y)=(y-4)*(2y+y^2)

User Isxek
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1 Answer

4 votes

Answer:


g'(y)=3y^2-4y-8

Explanation:

start by foiling out the given function


g(y)=(y-4)(2y+y^2)\\=2y^2+y^3-8y-4y^2\\=y^3-2y^2-8y

next, use the power rule to find the derivative

power rule: To use the power rule, multiply the variable's exponent n, by its coefficient a, then subtract 1 from the exponent. If there's no coefficient (the coefficient is 1), then the exponent will become the new coefficient.


g'(y)=3y^2-4y-8

User Terrence Brannon
by
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