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11 votes
11 votes
How do you determine whether (6,2) is on the line y=1/2x+2

User Hewigovens
by
2.5k points

2 Answers

26 votes
26 votes

Answer:

If the point
(6,2) does satisfy the equation,
y = (1)/(2)x +2\\, the point is on the line. Otherwise it's not.

Explanation:

Points that are on the line actually satisfy the equations of their respective lines. If the point
(6,2) does satisfy the equation,
y = (1)/(2)x +2\\, the point is on the line. Otherwise it's not.

Testing if
(6,2) is on the line,
y = (1)/(2)x +2\\:


y = (1)/(2)x +2 \\ 2 \stackrel{?}{=} (1)/(2)(6) +2 \\ 2 \stackrel{?}{=} 3 +2 \\ 2 \stackrel{?}{=} 3 +2 \\ 2 \stackrel{?}{=} 5 \\ 2 \\eq 5

The point
(6,2) does not satisfy the equation,
y = (1)/(2)x +2\\, so the point is not on the line.

User Snziv Gupta
by
2.5k points
8 votes
8 votes

Answer:

Graph the line y=1/2x+2 then check the points.

Explanation:

If I go on desmos, or just by hand and graph y=1/2x+2, I can see the points it goes through. Once I graph my equation, I will specifically type another coordinate "(6,2)" to see if it is directly in my line. For your equation, (6,2) is not in the line of y=1/2x+2.

I really hope this helps, ask anything else if needed.

User MoeinPorkamel
by
3.2k points
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