log₂(6-2x)=2
First of all, we have to understand what log₂ is referring to. When using logarithms with bases, we are looking at how many times does the base multiply by itself into the number. For example:
log₃(27) = 3
This shows that 3 multiplies into itself 3 times before achieving 27 aka 3³
So, for us to figure the answer to log₂(6-2x)=2, we have to multiply 2 by itself, which would make us get 4. So, the brackets would have to get us to 4. Therefore x would be 1
ANSWER: x=1