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Simplify 10 times the square root of quantity 3 x end quantity plus 4 times the square root of quantity 3 x end quantity plus 5 times the square root of quantity 3 x end quantity. 9 times the square root of quantity 3 x end quantity 9 times the square root of quantity 6 x end quantity 19 times the square root of quantity 3 x end quantity 19 times the square root of quantity 9 x cubed

2 Answers

6 votes


\\ \rm\dashrightarrow10√(3x)+4√(3x)+5√(3x)+9√(3x)+9√(6x)+19√(3x)+19√(9x^3)


\\ \rm\dashrightarrow (10+4+5+9+19)√(3x)+9√(6x)+19√(3^2x^2x)


\\ \rm\dashrightarrow 47√(3x)+9√(2x)√(3x)+57x√(x)


\\ \rm\dashrightarrow (47+9√(2x))√(3x)+57x√(x)

User Merigrim
by
3.4k points
4 votes

Answer:


19√(3x)

Explanation:

Given expression:


10 √(3x)+4√(3x)+5√(3x)

Given answer options:


  • 9√(3x)

  • 9√(6x)

  • 19√(3x)

  • 19√(9x^3)

To simplify the given expression, factor out
√(3x):


\implies 10 √(3x)+4√(3x)+5√(3x)


\implies √(3x)(10+4+5)

Add the numbers in the parentheses:


\implies √(3x)(19)

Rearrange to standard form:


\implies 19√(3x)

Therefore, the answer is the third option.

User Djcouchycouch
by
3.6k points