An object is dropped from the top of a tall building. The height S of the object after t seconds I’d given by the equation S = -16t^2+324. Find how many seconds pass before the object hits the ground.

AXM asked Jan 19, 2022

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24 votes

AXM asked Jan 19, 2022

by AXM

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27 votes

Answer:

Explanation:

0 = -16t² + 324

16t² = 324

t² = 20.25

t = 4.5 s

Nimsson answered Jan 25, 2022

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