Question

What is the equation of the line perpendicular to y = 5x +3 passing through the point (-3, 4)?

y=x+
y-**3
y = -2r +3
23
T3
y = -2 -2
y = +5
Donen

Answer 1

y =
`(1)/(5)`x + 19

Explanation:

Not sure what the stuff after "What is the equation of the line perpendicular to y = 5x +3 passing through the point (-3, 4)?" is, but I can create the equation from just that :D

So the equation will still be y = as it will be in slope intercept from (y=mx+b). The slope (m, or in this case currently it is 5) will change and be one-fifth as it is the opposite.

So far we have:

y =
`(1)/(5)`x + b

We then plug in the point (-3, 4) to figure out our b

(given) y = 5x + b

(plugging-in) 4 = 5(-3) + b

(mutiply) 4 = -15 + b

(adding 15 to both sides) 19 = b

Our equation will then be:

y =
`(1)/(5)`x + 19

Hopefully this is correct and helps, have a ncie day! :D