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19 votes
19 votes
A car reaches the interstate and increases its velocity from 25 m/s to 45 m/s in 5 s.

a. What is the car's acceleration?
b. How far did the car travel?

User Maecky
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1 Answer

11 votes
11 votes

Answer:

a) 4 m/s^2

b) 175 m

Step-by-step explanation:

Acceleartion is Δv/Δt. Δv = 45 - 25 = 20 m/s and Δt is 5 s. 20/5 = 4. From here we can use two approaches to solve for b

1)
d = v_(i) t + (1)/(2) at^(2), where d is distance,
v_(i) is the intital velocity, a is acceleration, and t is time

2)
d = (v_(i) + v_(f) )/(2) * t, where
v_(i) is the intital velocity,
v_(f) is the final velocity, and t is time.

If you plug in the numbers for either equation, you should get 175 m.

User Starikovs
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