Question

Solve the quadratic equation by using the quadratic formula. 2x^2-5x+1=0

Answer 1

`x = (5 + √(17) )/(4)`

Answer 2

Answer: x is 2.28 and 0.22

Explanation:

• From the quadratic formular of general equation ax² + bx + c = 0

`x = \frac{ - b± \sqrt{ {b}^(2) - 4ac } }{2a} \\`

• By comparison with equation given:

a » 2, b » -5, and c » 1

• substitute:

`x = \frac{ - ( - 5)± \sqrt{ {( - 5)}^(2) - (4 * 2 * 1) } }{(2 * 2)} \\ \\ x = (5± √(17) )/(4) \\ \\ x = 2.28 \: \: and \: \: 0.22`