218k views
0 votes
X2 +1/2x+____=2+____?

User Berriel
by
8.6k points

1 Answer

4 votes

Answer:


x^(2)+(1)/(2) x + (33)/(16)= 2 + (x + (1)/(4))^2

Explanation:


x^(2)+(1)/(2) x=x^(2)+2 * (1)/(4) * x +((1)/(4))^2 - ((1)/(4))^2


=[x^(2)+2 * (1)/(4) * x +((1)/(4))^2] - ((1)/(16))


=[x + (1)/(4)]^2 - ((1)/(16))

____________________

then


x^(2)+(1)/(2) x = [x + (1)/(4)]^2 - ((1)/(16)) -2 + 2

then


x^(2)+(1)/(2) x = [(x + (1)/(4))^2 - ((1)/(16)) -2] + 2

then


x^(2)+(1)/(2) x = [(x + (1)/(4))^2 - ((33)/(16)) ] + 2

then


x^(2)+(1)/(2) x = (x + (1)/(4))^2 - (33)/(16) + 2

then


x^(2)+(1)/(2) x + (33)/(16)= (x + (1)/(4))^2 + 2

then


x^(2)+(1)/(2) x + (33)/(16)= 2 + (x + (1)/(4))^2

User Deepak John
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories