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X2 +1/2x+____=2+____?
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X2 +1/2x+____=2+____?

User Berriel
by
3.7k points

1 Answer

4 votes

Answer:


x^(2)+(1)/(2) x + (33)/(16)= 2 + (x + (1)/(4))^2

Explanation:


x^(2)+(1)/(2) x=x^(2)+2 * (1)/(4) * x +((1)/(4))^2 - ((1)/(4))^2


=[x^(2)+2 * (1)/(4) * x +((1)/(4))^2] - ((1)/(16))


=[x + (1)/(4)]^2 - ((1)/(16))

____________________

then


x^(2)+(1)/(2) x = [x + (1)/(4)]^2 - ((1)/(16)) -2 + 2

then


x^(2)+(1)/(2) x = [(x + (1)/(4))^2 - ((1)/(16)) -2] + 2

then


x^(2)+(1)/(2) x = [(x + (1)/(4))^2 - ((33)/(16)) ] + 2

then


x^(2)+(1)/(2) x = (x + (1)/(4))^2 - (33)/(16) + 2

then


x^(2)+(1)/(2) x + (33)/(16)= (x + (1)/(4))^2 + 2

then


x^(2)+(1)/(2) x + (33)/(16)= 2 + (x + (1)/(4))^2

User Deepak John
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