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Consider the line 4x + 2y = 8.

What is the slope of a line perpendicular to this line?

User Shanequa
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1 Answer

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m1 x m2 = - 1

Rearrange 4x + 2y = 8.

4x + 2y = 8

-4x, then ÷ 2

y = - 4x + 8 / 2

y = - 2x + 4

m1 = - 2, find reciprocal of - 2, by placing 1 over the 2

So, - 2 will become - 1/2, but multiplying this gives us a positive 1. Thus, m2 = 1/2

m1 x m2 = - 1

-2 x 1/2 = - 1

That means slope perpendicular to the line

4x + 2y = 8 is y = 1/2x, where a half is the gradient/slope.

Ans: 1/2

Hope this helps!

User Mani Jagadeesan
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5.0k points