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Let x be a discrete random variable. if pr(x<9) = 1/6, and pr(x>9) = 1/3, then what is pr(x=9)?
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Let x be a discrete random variable. if pr(x<9) = 1/6, and pr(x>9) = 1/3, then what is pr(x=9)?

User James Davis
by
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1 Answer

4 votes

Answer: 1/2

Explanation:

The probabilities must add to 1, so:


P(x < 9) +P(X=9)+P(X > 9)=1\\\\(1)/(6)+P(X=9)+(1)/(3)=1\\\\P(X=9)=\boxed{(1)/(2)}

User Abhilash Reddy
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4.0k points
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