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What is the distance between (0,-8) and (3,2)

1 Answer

6 votes

Answer:
\Large\boxed{Distance=√(109)}

Step-by-step explanation:

Given information

(x₁, y₁) = (0, -8)

(x₂, y₂) = (3, 2)

Given the distance formula


Distance=√((x_2-x_1)^2+(y_2-y_1)^2)

Substitute values into the given formula


Distance=√((3-0)^2+(2-(-8))^2)

Simplify values in the parenthesis


Distance=√((3)^2+(2+8)^2)


Distance=√((3)^2+(10)^2)

Simplify the exponents


Distance=\sqrt{9+100

Simplify by addition


\Large\boxed{Distance=√(109)}

Hope this helps!! :)

Please let me know if you have any questions

User Electron
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