Question

2CO(g) + O2(g) = 2CO2(g)

If 6.0 L of CO reacts at STP, how many liters of oxygen are required for the reaction?

Answer 1

2CO(g) + O2(g) → 2CO2(g)

If 9.0 L of O2 react at STP, how

many moles of CO2 form during the

reaction?

[?] mol CO2

Step-by-step explanation:

What would it be if it was 9.0?

Answer 2

3.0 L O₂

Step-by-step explanation:

If CO reacts at STP, it means that there are 1.0 moles of CO. To find the moles of O₂, you need to use the mole-to-mole ratio from the given equation.

1.0 moles CO 1 mole O₂
---------------------- x --------------------- = 0.5 moles O₂
2 moles CO

To calculate the liters of oxygen, you need to use Avogadro's Law:

V₁ / N₁ = V₂ / N₂

In this equation, "V₁" and "N₁" represent the volume and moles of the first molecule. "V₂" and "N₂" represent the volume and moles of the second molecule. You can plug the given and calculated values into the equation and simplify to isolate V₂.

V₁ = 6.0 L V₂ = ? L

N₁ = 1.0 moles N₂ = 0.5 moles

V₁ / N₁ = V₂ / N₂ <----- Avogadro's Law

(6.0 L) / (1.0 moles) = V₂ / (0.5 moles) <----- Insert values

6.0 = V₂ / (0.5 moles) <----- Simplify left side

3.0 = V₂ <----- Multiply both sides by 0.5

**I am not 100% confident on this answer. Please let me know if it is incorrect**