The sum of 10 consecutive integersstarting with 11, equals the sum of 5 consecutive integers, starting with (A) 22 (B) 29 (C) 31 (D) 33

Question

asked Jun 15, 2023 43.2k views

1 Answer

Jeldrik · Answer 1 · 2023-06-19T17:07:40+0000

Answer:
$\large\boxed{29}$

Explanation:

The sum of 10 consecutive integersstarting with 11

= 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 155

Lets try 29:

29 + 30 + 31 + 32 + 33 = 155

Therefore our answer is:

$\large\boxed{29}$